Summary: in this tutorial, you will learn how to use the SQLite json_type()
function to return the type of a JSON element.
Introduction to the SQLite json_type() function
In SQLite, the json_type()
function returns the type of a JSON element. Here’s the syntax of the json_type()
function:
json_type(x)
Code language: SQL (Structured Query Language) (sql)
In this syntax:
x
is the JSON element of which you want to get the type.
If you want to get the JSON type of an element specified by a path, you can use the following syntax:
json_type(x, path)
Code language: SQL (Structured Query Language) (sql)
In this syntax, the json_type()
function returns the type of the element in x
selected by the path
.
The json_type()
function returns the following SQL text values:
- null
- false
- true
- integer
- real
- text
- array
- object
If the path does not exist in x, then the json_type()
function returns NULL
.
SQLite json_type() function examples
The following example uses the json_type()
function to return the json type of a JSON object:
SELECT json_type('{"name": "Joe"}');
Code language: SQL (Structured Query Language) (sql)
Output:
json_type('{"name": "Joe"}')
----------------------------
object
Code language: SQL (Structured Query Language) (sql)
The following example uses the json_type()
function to return the json type of a JSON array:
SELECT json_type('[1,2,3]');
Code language: SQL (Structured Query Language) (sql)
Output:
json_type('[1,2,3]')
--------------------
array
Code language: SQL (Structured Query Language) (sql)
The following example uses the json_type()
function to return the json type of the first element in a JSON array:
SELECT json_type('[1,2,3]', '$[1]');
Code language: SQL (Structured Query Language) (sql)
Output:
json_type('[1,2,3]', '$[1]')
----------------------------
integer
Code language: SQL (Structured Query Language) (sql)
The following example uses the json_type()
function to return the json type of the value of the name property in a JSON object:
SELECT json_type('{"name": "Joe"}','$.name');
Code language: SQL (Structured Query Language) (sql)
Output:
json_type('{"name": "Joe"}','$.name')
-------------------------------------
text
Code language: SQL (Structured Query Language) (sql)
The following example uses the json_type()
function to return the json type of the value of the active property in a JSON object:
SELECT json_type('{"name": "Joe", "active": true }','$.active');
Code language: SQL (Structured Query Language) (sql)
Output:
json_type('{"name": "Joe", "active": true }','$.active')
--------------------------------------------------------
true
Code language: SQL (Structured Query Language) (sql)
The following example uses the json_type()
function to return the json type of the value of a property that does not exist:
SELECT json_type('{"name": "Joe"}','$.age');
Code language: SQL (Structured Query Language) (sql)
Output:
json_type('{"name": "Joe"}','$.age')
------------------------------------
null
Code language: SQL (Structured Query Language) (sql)
The following statement uses the json_type()
function to return the json type of the value of the age property:
SELECT json_type('{"name": "Joe", "age": 25}','$.age');
Code language: SQL (Structured Query Language) (sql)
Output:
json_type('{"name": "Joe", "age": 25}','$.age')
-----------------------------------------------
integer
Code language: SQL (Structured Query Language) (sql)
The following statement uses the json_type()
function to return the json type of the value of the weight property:
SELECT json_type('{"name": "Joe", "age": 25, "weight": 176.37}','$.weight');
Code language: SQL (Structured Query Language) (sql)
Output:
json_type('{"name": "Joe", "age": 25, "weight": 176.37}','$.
------------------------------------------------------------
real
Code language: SQL (Structured Query Language) (sql)
Summary
- Use the
json_type(x)
function to get the JSON type of the outermost element of x. - Use the
json_type(x, path)
function to obtain the JSON type of the element in x specified by the path.