Summary: in this tutorial, you will learn about various ways to show the structure of a table in SQLite.
Getting the structure of a table via the SQLite command-line shell program
To find out the structure of a table via the SQLite command-line shell program, you follow these steps:
First, connect to a database via the SQLite command-line shell program:
sqlite3 c:\sqlite\db\chinook.db
Code language: SQL (Structured Query Language) (sql)
Then, issue the following command:
.schema table_name
Code language: SQL (Structured Query Language) (sql)
For example, the following command shows the statement that created the albums
table:
.schema albums
Code language: SQL (Structured Query Language) (sql)
Notice that there is no semicolon (;
) after the table name. If you add a semicolon (;
), the .schema
will consider the albums;
as the table name and returns nothing because the table albums;
does not exist.
Here is the output:
CREATE TABLE IF NOT EXISTS "albums"
(
[AlbumId] INTEGER PRIMARY KEY AUTOINCREMENT NOT NULL,
[Title] NVARCHAR(160) NOT NULL,
[ArtistId] INTEGER NOT NULL,
FOREIGN KEY ([ArtistId]) REFERENCES "artists" ([ArtistId])
ON DELETE NO ACTION ON UPDATE NO ACTION
);
CREATE INDEX [IFK_AlbumArtistId] ON "albums" ([ArtistId]);
Code language: SQL (Structured Query Language) (sql)
Another way to show the structure of a table is to use the PRAGMA
command. To do it, you use the following command to format the output:
.header on
.mode column
Code language: SQL (Structured Query Language) (sql)
And use the PRAGMA
command as follows:
pragma table_info('albums');
Code language: JavaScript (javascript)
The following picture shows the output:
cid name type notnull dflt_value pk
--- -------- ------------- ------- ---------- --
0 AlbumId INTEGER 1 1
1 Title NVARCHAR(160) 1 0
2 ArtistId INTEGER 1 0
Getting the structure of a table using the SQL statement
You can find the structure of a table by querying it from the sqlite_schema
table as follows:
SELECT sql
FROM sqlite_schema
WHERE name = 'albums';
Code language: SQL (Structured Query Language) (sql)
Here is the output:
sql
------------
CREATE TABLE "albums"
(
[AlbumId] INTEGER PRIMARY KEY AUTOINCREMENT NOT NULL,
[Title] NVARCHAR(160) NOT NULL,
[ArtistId] INTEGER NOT NULL,
FOREIGN KEY ([ArtistId]) REFERENCES "artists" ([ArtistId])
ON DELETE NO ACTION ON UPDATE NO ACTION
)
Code language: SQL (Structured Query Language) (sql)
In this tutorial, you have learned how to show the structure of a table in SQLite via a command-line shell program or SQL statement.