Summary: in this tutorial, you will learn how to use SQLite COUNT
function to get the number of items in a group.
Introduction to SQLite COUNT() function
The function COUNT()
is an aggregate function that returns the number of items in a group.
For example, you can use the COUNT()
function to get the number of tracks from the tracks
table, the number of artists from the artists
table, and so on.
The following illustrates the basic syntax of the COUNT
function:
COUNT([ALL | DISTINCT] expression);
Code language: SQL (Structured Query Language) (sql)
Arguments
The COUNT
function behaves according to the arguments that you pass into it and the option ALL
or DISTINCT
that you specify.
The following describes the meanings of ALL
and DISTINCT
options:
ALL
: when you specify all, theCOUNT()
function counts all non-null values include duplicates. TheCOUNT()
function uses theALL
option by default if you skip it.DISTINCT
: if you explicitly use theDISTINCT
option, theCOUNT
function counts only unique and non-null values.
The expression can be a column or an expression that involves columns to which the function COUNT()
is applied.
SQLite provides another syntax of the COUNT()
function:
COUNT(*)
Code language: SQL (Structured Query Language) (sql)
The COUNT(*)
function returns the number of rows in a table, including the rows including NULL and duplicates.
SQLite COUNT() function illustration
First, create a table called t1
that has one column:
CREATE TABLE t1(c INTEGER);
Code language: SQL (Structured Query Language) (sql)
Second, insert five rows into the t1
table:
INSERT INTO t1(c)
VALUES(1),(2),(3),(null),(3);
Code language: SQL (Structured Query Language) (sql)
Third, query data from the t1
table:
SELECT * FROM t1;
Code language: SQL (Structured Query Language) (sql)
Fourth, use the COUNT(*)
function to return the number of rows in the t1
table:
SELECT COUNT(*) FROM t1;
Code language: SQL (Structured Query Language) (sql)
As you can see clearly from the output, the result set includes NULL and duplicate rows.
Fifth, use the COUNT(expression)
to get the number of non-null values in the column c
:
SELECT COUNT(c) FROM t1;
Code language: SQL (Structured Query Language) (sql)
In this example, the COUNT(c)
returns the number of non-null values. It counts the duplicate rows as separate rows.
Sixth, use the COUNT(DISTINCT expression)
to get the number of unique and non-null values in column c
:
SELECT COUNT(DISTINCT c) FROM t1;
Code language: SQL (Structured Query Language) (sql)
SQLite COUNT(*) examples
We will take the table tracks
in the sample database to demonstrate the functionality of the COUNT(*)
function.
1) SQLite COUNT(*) example
To get the number of rows from the tracks
table, you use the COUNT(*)
function as follows:
SELECT count(*)
FROM tracks;
Code language: SQL (Structured Query Language) (sql)
count(*)
--------
3503
Code language: plaintext (plaintext)
2) SQLite COUNT(*) with WHERE clause example
The following statement uses the COUNT(*)
function with a WHERE
clause to find the number of tracks whose album id is 10:
SELECT COUNT(*)
FROM tracks
WHERE albumid = 10;
Code language: SQL (Structured Query Language) (sql)
COUNT(*)
--------
14
3) SQLite COUNT(*) with GROUP BY clause example
To get all the albums and the number of tracks in each album, you combine the COUNT(*)
function with the GROUP BY
clause:
SELECT
albumid,
COUNT(*)
FROM
tracks
GROUP BY
albumid;
Code language: SQL (Structured Query Language) (sql)
AlbumId COUNT(*)
------- --------
1 10
2 1
3 3
4 8
5 15
6 13
7 12
8 14
9 8
10 14
...
In this example:
- First, the
GROUP BY
clause group tracks by album id. - Then, the
COUNT(*)
function returns the number of tracks for each album or group of tracks.
4) SQLite COUNT(*) with HAVING clause example
The following uses the COUNT(*)
in the HAVING
clause to find albums that have more than 25 tracks:
SELECT
albumid,
COUNT(*)
FROM
tracks
GROUP BY
albumid
HAVING COUNT(*) > 25
Code language: SQL (Structured Query Language) (sql)
AlbumId COUNT(*)
------- --------
23 34
73 30
141 57
229 26
5) SQLite COUNT(*) with INNER JOIN clause example
In order to make the output of the above query more useful, you can include the album’s name column. To do this, you add INNER JOIN
and ORDER BY
clauses to the query like the following query:
SELECT
tracks.albumid,
title,
COUNT(*)
FROM
tracks
INNER JOIN albums ON
albums.albumid = tracks.albumid
GROUP BY
tracks.albumid
HAVING
COUNT(*) > 25
ORDER BY
COUNT(*) DESC;
Code language: SQL (Structured Query Language) (sql)
AlbumId Title COUNT(*)
------- -------------- --------
141 Greatest Hits 57
23 Minha Historia 34
73 Unplugged 30
229 Lost, Season 3 26
SQLite COUNT(DISTINCT expression) examples
Let’s take a look at the employees
table from the sample database.
SELECT
employeeid,
lastname,
firstname,
title
FROM
employees;
Code language: SQL (Structured Query Language) (sql)
EmployeeId LastName FirstName Title
---------- -------- --------- -------------------
1 Adams Andrew General Manager
2 Edwards Nancy Sales Manager
3 Peacock Jane Sales Support Agent
4 Park Margaret Sales Support Agent
5 Johnson Steve Sales Support Agent
6 Mitchell Michael IT Manager
7 King Robert IT Staff
8 Callahan Laura IT Staff
To get the number of position titles, you pass the title
column to the COUNT()
function as follows:
SELECT COUNT(title)
FROM employees;
Code language: SQL (Structured Query Language) (sql)
COUNT(title)
------------
8
However, to get the number of unique titles, you need to add the DISTINCT
option to the COUNT()
function as shown in the following statement:
SELECT COUNT(DISTINCT title)
FROM employees;
Code language: SQL (Structured Query Language) (sql)
COUNT(DISTINCT title)
---------------------
5
In this tutorial, we have shown you how to use SQLite COUNT()
function to count the number of items in a group.